a body of mass 500 kg kept at rest breaks into two parts due to internal force 1 part of mass 200 gram is found to move at the speed of 10 metre per second towards the east what will be the velocity of the other part?
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The velocity of the other object will be equal to 4mm/sec towards west
Explanation:
Given that the total mass of the body is equal to 500 kilogram.
- the mass of one object which is moving towards the east direction is equal to 200gm or 0.2kg and its velocity is 10 metre per second
- Hence the mass of the other object will be equal to 499.8kg
- By the conservation of linear momentum the linear momentum will remain equal initially and finally. In the above question is given that the body was at least initially. Hence the linear momentum is equal to zero , hence the final momentum should also be equal to zero
- so if one of the object moves in the east direction the other will move in the opposite that is the west direction to nullify the linear momentum. Also the magnitude of the linear momentum of the two objects will be equal but in the opposite direction
- Hence,
- 499.8 x v= 0.2x10
- V= 2/499.8 = 4x 10^-3 or 4mm/sec towards west
To know more,
name the two application of the laws of conservation of linear ....https://brainly.in/question/4992144
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