Question

a body of mass 500g is at rest on a frictionless surface. How much the distance travelled by it in 10s when acted upon by a force of 10^-2 N...

Please if you know answer then and then only answer it. ​

Answer 1

Answer:

Distance traveled in 10 seconds = 1 metre

Explanation:

Given :

A body of mass 500 g is at rest on a frictionless surface.

When the body is acted upon by a force of $10^{-2}$N,

then find distance traveled by the body in 10 seconds .

Solution :

We know that,

Force = Mass × Acceleration ( F = ma )

Force (F) = $10^{-2}$N = 0.01 N

Mass (m) = 500 g = 0.5 kg

⇒ F = ma

⇒ $0.01 = 0.5a$

⇒ $\frac{0.01}{0.5} = a$ ⇒ a = 0.02 m/s²

We also knew that,

Distance traveled (s) = ut + ¹/₂ at²   (here , s meant distance travelled)

here u = 0 m/s

t = 10 seconds.

a = 0.02 m/s²

⇒ $s = ut +\frac{1}{2} at^2$

⇒ $s = 0 \times 10 +\frac{1}{2} \times 0.02 \times (10)^2$

⇒ $s = 0 + 0.01 \times 100$ = 1 m

Answer 2

Answer:

Refer to the above image .....

Explanation:

Hope it will help you .....