Question

a body of mass 500g is moving on a circular path or radius 0.5m if it makes 28 revolutions in 8 seconds and the speed is uniform. calculate the centripetal force if it maintains the motion
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Answer 1

$radius(r) = 0.5 \: m \\ circumference(c) = \: 2\pi \: r \\ = 2 \times \frac{22}{7} \times 0.5 \\ = 2 \times \frac{11}{7} \\ = \frac{22}{7} \\ distance \: covered \: in \: 1 \: revolution = \frac{22}{7} m \\ dist. \: covered \: in \: 28 \: revolu. = 28 \times \frac{22}{7} \\ = 4 \times 22 \\ = 88 \: m \\ speed = \frac{distance}{time} \\ s = \frac{88}{8} \\ s = 11 m{s}^{ - 1 } \\ acceleration = \frac{v - u}{t} \\ a = \frac{11 - 0}{8} \\ (put \: u = 0 \: because \: the \: body \: started \: from \: rest) \\ a = \frac{11}{8} m {s}^{ - 2} \\ force = mass \times acceleration \\ f = 500 g \times \frac{11}{8} \\ = 0.5 \: kg \times \frac{11}{8} \\ = \frac{5.5}{8} \\ = 0.6875 \: newton$

Answer 2

Answer:

0.6875 Newton

it's your answer hope this helps ☺☺

btw nice ❤☺