Question

a body of mass 50kg is pulled by a rope of length 6m on a surface by a force 106N applied at the other end. The linear density of the rope is 0.5kg/m. The force acting on 50g mass is?​

Answer 1

$here \: is \: the \: answer \: mate \\ \\ see \: the \: attachment \: for \: figure \\ \\ we \: have \: a \: rope \: of \: mass \: = 0.5 \times 6m = 3kg \\ \\ f= ma \\ 105 = (50 + 3)a \\ a = \frac{106}{53} \\ a = 2m {s}^{ - 1} \\ \\ so \: the \: forc \: acting \: on \: the \: 50kg \: mass \: will \: be \\ f = ma \\ f = 50 \times 2 \\ = 100 \: newton$

Answer 2

Answer:

Explanation:

Answer in

http://clay6.com/qa/11215/a-body-of-mass-50-kg-is-pulled-by-a-rope-of-length-8-m-on-a-surface-by-a-fo