Question

A body of mass 5gm is executing simple harmonic motion abpit a point O qith amplitude 10 cm its maximum velocity is 100cm/sec calculate velocity at distance 5cm
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Answer 1

Mass of the body= 5 gm

amplitude, a=10 cm

Maximum velocity= 100 cm/sec

if a body execute S.H.M.,

Maximum velocity= a*omega        (where omega is an angular velocity of the body)

So,

Maximum velocity= a*omega= 100

omega= 100/10= 10 per sec

As we know,

v= omega*(a^2-y^2)^(1/2)

For v=50

50=10(10^2-y^2)^(1/2)

(10^2-y^2)^(1/2)=5

Squaring both sides

100-y^2=25

y^2=100-25=75

Taking square root both side, we get:

y=8.7

Therefore, velocity = 50cm/sec at the distance of 8.7cm

Thanks

Mark brainliest

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