Question

a body of mass 5kg having a velocity of 80 m/s¹ experience a force in the opposite direction .the body is brought to rest in 8 sec. what is the retardation produced by the force?​

Answer 1

Answer:

m= 5kg

u=80m/s

v=0m/s

t= 8s

a= (v-u/t)

a=(0-80/8)

a= -10 m/s^2

F=ma

F=5 × (-10)

F= -50 N or 50 kg×m/s

Hope it helps!