A body of mass 5kg initial at rest is subjected to a force of 20n find the kinetic energy acquired by the body at the end of 10 seconds
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here mass = 5kg and force = 20N
therefore acceleration => 20/5 = 4m/s^2
and u = 0 and time = 10 sec
therefore final velocity (v) = u+at
=> v= 0+4*10. => v = 40m/s
therefore kinetic energy = 1/2*m*v^2
=> 1/2*5*40*40 => 4000J
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therefore acceleration => 20/5 = 4m/s^2
and u = 0 and time = 10 sec
therefore final velocity (v) = u+at
=> v= 0+4*10. => v = 40m/s
therefore kinetic energy = 1/2*m*v^2
=> 1/2*5*40*40 => 4000J
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babalpreet2003:
Good work
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1
F=ma
F= 20N, m=5kg
so a=20/5
=4m/s²
now v= u+at
u=0
v=at
v=4×10=40. (t = 10 sec)
KE =½mv²=1/2×5×(40)²
=4000J
F= 20N, m=5kg
so a=20/5
=4m/s²
now v= u+at
u=0
v=at
v=4×10=40. (t = 10 sec)
KE =½mv²=1/2×5×(40)²
=4000J
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