Physics, asked by tstechandgaming1999, 2 months ago

A body of mass 5Kg is dropped from the top of a tower of height 100m. What will be
kinetic energy at the end of 2 second. (Given g =9.8m/s2)​

Answers

Answered by shivasinghmohan629
1

Answer:

Explanation:

K=(1/2) my^2 is the formuláe for kinetic energy (K).

Explanation:

In order to test the dimensional consistency, the required conditions are:

i). Each equation or formulae should have similar dimensions on the equation's both sides.

The proportions of an equation for kinetic energy on L.H.S. would be

{k} = {ML²T-2}

Thus, the dimensions on R.H.S. would be K=(1/2) mv^2 as it correctly goes with the definition of kinetic energy.

Learn more: Sl unit of energy

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