Question

A body of mass 5kg is taken from a height of 3m to 6m.Calculate the following:

(i) Initial potential energy.

(ii) Final potential energy.

(iii) The change in total potential energy

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Answer 1

Given :

• Mass = 5 kg
• Initial height = 3 m
• Final height = 6 m

To find :

• Initial potential energy
• Final potential energy
• Change in total potential energy

According to the question,

i) Initial potential energy

➞ P = mgh

Where,

• P = Potential energy
• m = Mass
• g = Acceleration due to gravity
• h = Height of the body

➞ P = 5 × 10 × 3

➞ P = 150 J

So,the initial potential energy is 150 J.

ii) Final potential energy

➞ P = mgh

➞ P = 5 × 10 × 6

➞ P = 300 J

So,the final potential energy is 300 J.

iii) Change in total potential energy

➞ Change in total potential energy = Final potential energy - Initial potential energy

➞ Change in total potential energy = 300 - 150

➞ Change in total potential energy = 150 J

So,the change in total potential energy is 150 J.

Answer 2

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A body of mass 5kg is taken from a height of 3m to 6m.Calculate the following:

(i) Initial potential energy.

(ii) Final potential energy.

(iii) The change in total potential energy

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• $Weight (m) =5kg$
• $Initial height=3m$
• $Final height=6m$

${ { \underbrace{ \mathbb{ \red{To\:PrOvE\ }}}}}$

• $A)\: Initial\: potential\: energy.$

• $B) \:Final \:potential \:energy.$

• $C) \:The \:change\: in\: total \:potential\: energy$

${ \color{aqua}{ \underbrace{ \underline{ \color{lime}{ \mathbb{\star SoLuTiOn\star }}}}}}$

______________________________________

$\huge \bold {A)\: Initial\: potential\: energy}$

${\boxed {\boxed {PE=mgh}}}$

• $PE= Potential \:energy$
• $m=weight$
• $g= Acceleration\: due\: to\: gravity$
• $h=Initial\: height\: of\: the \:body$

$Substitute\: the\: values$

$PE=5\times 10\times 3$

${\boxed {\boxed {PE=150J}}}$

$\therefore Initial\: Potential \:Energy \:is \:{\boxed {\boxed {150J}}}$

______________________________________

$\huge \bold {B) \:Final \:potential \:energy}$

• $PE= Potential \:energy$
• $m=weight$
• $g= Acceleration\: due\: to\: gravity$
• $h=Final \: height\: of\: the \:body$

$Substitute\: the\: values$

$PE=5\times 10\times 6$

${\boxed {\boxed {PE=300J}}}$

$\therefore Final\: Potential \:Energy \:is \:{\boxed {\boxed {300J}}}$

______________________________________

$\huge\bold{C) \:The \:change\: in\: total \:potential\: energy}$

$Change\: in\: total \:potential\: energy=Final \:potential \:energy-Initial\: potential\: energy$

$Change\: in\: total \:potential\: energy=300-150$

$Change\: in\: total \:potential\: energy=150$

$\therefore Change\: in\: total \:potential\: energy \:is {\boxed {\boxed {150J}}}$

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${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5069}}}}}}}}}}}}}}}$