Physics, asked by safnasiyad16, 9 months ago

A body of mass 5kg is thrown vertically up with a kinetic energy of 490j. Find the height at which the kinetic energy of the body becomes half of the original value

Answers

Answered by vidhi7367

3

Answer:

H=4.9m

Explanation:

KE=KE/2+mgh

KE/2=mgh

490/2=5×10h

h=490/(2×5×10)=4.9

Previous Question

Next Question

Similar questions

Math, 4 months ago

rationalise the denominator = 1 / ✓5 +✓3...

Hindi, 4 months ago

गोपियाँ किसके साथ संवाद कर रहीं हैं? और क्यों? .

Math, 4 months ago

find two positive integer x and dy unday 3 Set...

Chemistry, 9 months ago

please answer it with explaination...

Math, 9 months ago

What is Fraction?????

Math, 11 months ago

Mrs. Conley asks her class what kind of party they want to have to celebrate their excellent behavior. Out of all the students in the class, 55 want an ice cream party, 77 want a movie party, 1010 want a costume party, and the rest are undecided. If 20\%20% want an ice cream party, how many students are in the class?

Social Sciences, 11 months ago

What crops are not suitable for dry land agriculture...

English, 11 months ago

flies carry many diseases.(passive voice)...