Question

A body of mass 6 kg accelerates from 6 m/s to 18 m/s in 3 seconds due to the application of a force on it. Calculate the magnitude of this force (in N)

Answer 1

Answer:

Force is 24N.

Step-by-step explanation:

We know,

F = m*a ---- (Newton's second law of motion)

acceleration = v-u/t

Therefore, a is 4.

And mass is 6kg.

Therefore,

F = m*a

F = 6*4

F = 24N.

Answer 2

Answer:

The required force is 24 N

Step-by-step explanation:

Given :

A body of mass 6 kg accelerates from 6 m/s to 18 m/s in 3 seconds due to the application of a force on it.

To find :

the magnitude of the force

Solution :

First, let's find the acceleration of the given object.

We know, acceleration is the rate of change of velocity.

$\boxed{\sf a = \dfrac{v-u}{t}}$

where

v denotes the final velocity

u denotes the initial velocity

t denotes the time taken

______________________

Given,

u = 6 m/s

v = 18 m/s

t = 3 s

So, acceleration, a = (18 - 6)/3

a = 12/3

a = 4 m/s²

Therefore, the acceleration is 4 m/s²

______________________

We know,

$\longmapsto \rm F=ma$

where

m denotes the mass of the body

a denotes it's acceleration.

=> F = 6 kg × 4 m/s²

=> F = 24 kg m/s²

=> F = 24 N