a body of mass 60 kg running at 3 metre per second jumps onto a trolley of mass 740 kg moving with a velocity of 1.5 m per second in the same Direction. What is the common velocity?
Answers
Answered by
1
Applying conservation of linear momentum
MU+mu = (M+m)v
(60000×3) + (740000×1.5) = (60000+740000)v
180000+1110000 = 800000v
= 1290000= 800000v
= v = 1290000/800000
v= 1.61 m/s
MU+mu = (M+m)v
(60000×3) + (740000×1.5) = (60000+740000)v
180000+1110000 = 800000v
= 1290000= 800000v
= v = 1290000/800000
v= 1.61 m/s
Similar questions