Question

a body of mass 600 grams is at rest on a frictionless surface calculate the distance travelled by it in 20 seconds when acted upon by a force of 10^-2 Newton​​

Answer 1

Given:

• Initial velocity, u = 0 m/s (as it is at rest)
• Time taken = 20 seconds
• Force acted on body, F = 10² N = 0.01 N
• Mass, m = 600 g

To Find:

• Distance travelled

Solution:

Body of mass = 600 g = 0.6 kg

According to the question:

★ F = ma

Here,

• F = Force
• a = Acceleration
• m = mass

Putting the values:

→ 0.01 = 0.6 × a

→ 0.01 ÷ 0.6 = a

→ 0.0167 = a

• So the acceleration is 0.0167 m/s²

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Now,

Finding the distance travelled

★ Newton's third equation of motion

→ s = ut + 1/2 at²

Here,

• s = distance travelled
• u = Initial velocity
• a = acceleration
• t = time

Putting the values:

→ s = 0 × 20 + 1/2 × 0.0167 × 20 × 20

→ s = 0 + 0.0167 × 10 × 20

→ s = 0 + 0.0167 × 200

→ s = 0 + 3.34

→ s = 3.34

• So the distance travelled by body = 3.34 m

Hence,

• Distance travelled by body = 3.34 m.