Question

a body of mass 60kg hung by a spring balance in a lift what will be the weight ?when the lift is descending with a constant velocity 2.5m/s​

Answer 1

Explanation:

Given that,

Given that,Mass of body m=10kg

Given that,Mass of body m=10kgAcceleration a=2m/s2

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an acceleration

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg(II). the descending with the same acceleration

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg(II). the descending with the same acceleration  mg−T=ma

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg(II). the descending with the same acceleration  mg−T=ma T=mg−ma

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg(II). the descending with the same acceleration  mg−T=ma T=mg−ma gT=m−gma

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg(II). the descending with the same acceleration  mg−T=ma T=mg−ma gT=m−gma gT=10−1010×2

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg(II). the descending with the same acceleration  mg−T=ma T=mg−ma gT=m−gma gT=10−1010×2 gT=10−2

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg(II). the descending with the same acceleration  mg−T=ma T=mg−ma gT=m−gma gT=10−1010×2 gT=10−2 gT=8kg

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg(II). the descending with the same acceleration  mg−T=ma T=mg−ma gT=m−gma gT=10−1010×2 gT=10−2 gT=8kg (III). the descending with a constant velocity

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg(II). the descending with the same acceleration  mg−T=ma T=mg−ma gT=m−gma gT=10−1010×2 gT=10−2 gT=8kg (III). the descending with a constant velocity  T−mg=0

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg(II). the descending with the same acceleration  mg−T=ma T=mg−ma gT=m−gma gT=10−1010×2 gT=10−2 gT=8kg (III). the descending with a constant velocity  T−mg=0 T=mg

Given that,Mass of body m=10kgAcceleration a=2m/s2 (I). The lift is ascending with an accelerationAccording to figure   T−mg=ma T=ma+mg gT=m+gma gT=10+1010×2 gT=12kg(II). the descending with the same acceleration  mg−T=ma T=mg−ma gT=m−gma gT=10−1010×2 gT=10−2 gT=8kg (III). the descending with a constant velocity  T−mg=0 T=mg