Question

A body of mass 60kg rests on a horizontal plane. The value of co-efficient of friction between it and the plane being 0.2. Find the work(m-kg) done in moving the body through a distance of 5 meters along the plane.​

Answer 1

Answer:

that a body of mass 60 kg rests on hori

Answer 2

Answer:

A body of mass 60kg rests on a horizontal plane. The value of the coefficient of friction between it and the plane is 0.2. The work done in moving the body through a distance of 5 meters along the plane will be $588 \ Nm$

Explanation:

• Let W be the work done to move an object, F be the force applied and x be the distance moved by the object, we know the work done to move a body is the product of the force applied to the object and the distance moved by the object.

       Then,

        $W = F\times x$     ...(1)

• Force can be obtained by using the expression,

        $F = \mu mg$        ...(2)

         Where

         $\mu$  - the coefficient of friction

         m - Mass of the object and

         g - the acceleration due to gravity.

• In the question, it is given that,

       $m = 60\ kg$           $\mu = 0.2$          $x = 5m$

       We know,

       $g = 9.8m/s^2$

       Substituting these values into equation (2),

      $F = 0.2\times 60\times 9.8 = 117.6 N$

      Then using equation(1),

      $W = 117.6\times 5 = 588 \ Nm$