A body of mass 70 kg has the momentum 4000kgms^-1 . find the kinetic energy.
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. Given Question:-
. A body of mass 70 kg has the momentum 4000kgms^-1 . find the kinetic energy.
. Answer:-
. Given,
m = 70kg
p = 4000kgms^-1
. Therefore, Kinetic energy =
= 1 / 2 × ( mv)^2 / m = 1 / 2 × p^2 / m
= 1 / 2 × ( 4000)^2 / 70 =
= 1, 142, 857.14 J
= 1, 142 J
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