Question

a body of mass 70 kg when completely immersed in water difference is 20,000 cm cube of water. Find the weight of a body in water and the relative density of material of body.

Answer 1

the formula for weight of the body is mass multiplied by g =m*g=70*10 =700 kgwt (as we know g=10m/s^2) .density is mass per volume=m/v. 20000cm^3 =0.02m^3. density =70/0.02=3500kg/m^3

Answer 2

$\textbf{\huge{ANSWER:}}$

Given:
Mass = 70 kg
Weight of water displaced = 2000${cm}^{3}$

Weight = 2000${cm}^{3}$

=》 2×${10}^{-3} {cm}^{3}$

Density of the substance = $\frac{70}{2 \times {10}^{-3}}$

=》 $35 \times{10}^{3}$

Relative Density = $\frac{Density\:of\:substance}{Density\:of\:water}$

=》 $\frac{35 \times{10}^{3}}{{10}^{3}}$

=》 $\textbf{35}$

Hope it Helps!! :)