Question

a body of mass m fall from height h1 to h2 above the ground. calculate the loss potential energy of a ball​

Answer 1

Answer:

At height h1, initial potential energy of the body = mgh1

At height h2, final potential energy of the body = mgh2

Loss in potential energy = Initial potential energy - Final potential energy

= mgh1 - mgh2 = mg (h1 - h2)

Answer 2

Answer:

At height h1, initial potential energy of the body = mgh1 

At height h2, final potential energy of the body = mgh2 

Loss in potential energy =  Initial potential energy - Final potential energy

= mgh1 - mgh2 = mg (h1 - h2)