Question

A body of mass m is dropped from a height h on a hard smooth horizontal surface it bounces back to smae height ,the magnitude of charge in momentum of body is (-ve is for away from the floor)
a). -m√2gh
d). +m√2gh
c). 0
d). +2m√2gh

Answer 1

Charge in momentum or change in momentum?

Answer 2

we know that, momentum(P) = mass × velocity

but, v = square root of 2gh

therefore, change in P = m× square root of 2gh - (- square root of 2gh)

therefore, change in P = 2m× square root of 2gh