A body of mass m is moving in a circle of radius r
with a constant speed v. The work done by the
centripetal force in moving the body over half
the circumference of the circle is
(a) mv²r (b) zero
(c) mv²/r (d) r²/m v²
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Answer:
ZERO IS THE ANSWER
Explanation:
Velocity vector is always tangential to circle.
The Force acting towards the centre will some F1.
The angle between velocity vector and force is 90°.2
We know that,
W=F.d .........(d=vt)
W=F1 . vt cos 90°
W= F1 .0
W=0
Hence work done is 0 in moving the body over half the circumference of circle.
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