Question

a body of mass M is projected from ground for horizontal range are at highest point it is segmented into 2 identical parts if one part return back to the point of education then other part will have a horizontal to range

Answer 1

Let u be the horizontal velocity given to the particle of mass m.

R be the horizontal range.

Till reaching to the highest point, horizontal distance travelled is given is R/2

At the highest point, it gets break into two parts, each of mass m/2

According to the law of conservation of momentum mu= mu1/2−mu^2/2

u1 =2 u+u2

Both have different direction particle moving with velocity u2 reached to the initial position.

Horizontal distance travelled by this particle in time t is given by:

R/2= u2 t

u2= R/2t

Distance travelled by particle moving with velocity u1 is given by;

x = (2u+u2)t

x = 2ut + u2t

x = 2uT/2 +u2t

x = R+R/2

x  = 3R/2

Range is given by= initial horizontal distance travelled before breaking + x range = 3R/2+R/2 = 2R

Answer 2

Answer:  2R

Explanation:

Refer to the attachments below.....

Suggest if any mistake....

Hope it helps.....