a body of mass m is projected with a velocity 6i+8j.find change in momentum when it just touches the ground
Answers
Answered by
5
here if the body is released vertically the after the mass hitting the ground only the y component changes its direction and becomes negative
hence the velocity becomes 6i-8j
therefore change in momentum i.e., Δmv=mx16i
hence the velocity becomes 6i-8j
therefore change in momentum i.e., Δmv=mx16i
Answered by
0
Answer: Zero
Explanation:
- Momentum is defined as the product of mass of the body and the velocity with which it is moving.
- It is denoted ny letter P.
- We can say, P= mass × velocity
or P= m × v
- Here, the velocity vector is 6i + 8j.
- When a body just touches the ground then its velocity becomes zero.
- So we can say that the momentum of the body when it just touches the ground is zero.
- Hence, the required answer is zero.
#SPJ3
Similar questions