A body of mass m is released from a point at a height h above thesurface ofte earth.Show that uts velocity (v) when itvstruck the rath surfaceis guven by
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as the body is released = u = 0
v=?
a=g
s=h
![{v}^{2} - {u}^{2} = 2as {v}^{2} - {u}^{2} = 2as](https://tex.z-dn.net/?f=+%7Bv%7D%5E%7B2%7D++-++%7Bu%7D%5E%7B2%7D++%3D+2as)
![{v}^{2} - {0}^{2} = 2gh {v}^{2} - {0}^{2} = 2gh](https://tex.z-dn.net/?f=+%7Bv%7D%5E%7B2%7D++-++%7B0%7D%5E%7B2%7D++%3D+2gh)
![{v}^{2} = 2gh {v}^{2} = 2gh](https://tex.z-dn.net/?f=+%7Bv%7D%5E%7B2%7D++%3D+2gh)
![v = \sqrt{2gh} v = \sqrt{2gh}](https://tex.z-dn.net/?f=v+%3D++%5Csqrt%7B2gh%7D+)
this is the velocity with which the body will strike the earth on falling from height h
v=?
a=g
s=h
this is the velocity with which the body will strike the earth on falling from height h
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