Question

A body of mass m is taken from Earth's surface to the height equal to half of radius of Earth . The increase in potential energy will be ?​

Answer 1

Answer:

(2/3)*mgh

Explanation:

∆U=mgh/(1+h/R)

=mgh/(3/2)

Answer 2

the gravitational potential energy at a height h is UH GM- em/Re+h If h Re Uh -GM-em/+2R-e -mgR- e/2& the gravitational potential energy