Question

a body of mass m is thrown up with a kinetic energy of 490 joules what is the height at which the kinetic energy of the body becomes half of the original value

Answer 1

Here Mass=m kg,g=9.8m/s2 ,now When Kinetic Energy Was 490 Its Height Was 0,therefore Potential Energy Was 0,when Its Kinetic E. Is Half ,the Left Half Energy Is Shared With Potential Energy,then We Can Write 490/2=mgh ,therefore We Can Get 2450/m98