Question

A body of mass m moving with a velocity v is acted upon by a force. Write an expression for the change in momentum in each of the following cases: (i) when v << c, (ii) when v → C, and (iii) when v << c but m does not remain constant. Here c is the speed of light​

Answer 1

Answer:

As we know that momentum (p) =MAASS×VELOCITY(vector quantity)

hence chance in momentum(Δp)=m2v2−m1v1=Δ(mv)

where m1=m2=m

Δv=v2−v1

I hope it helps you.

Answer 2

momentum (p) =MAASS×VELOCITY(vector quantity)

hence chance in momentum(Δp)=m2v2−m1v1=Δ(mv)

where m1=m2=m

Δv=v2−v1

Mark me as brainliest pls!!