Question

A body of mass m rises to a heighth=R/5 from the earth's surface where R is earth's radius. If g is acceleration due to gravity at the earth's surface, the increase
in potential energy is?​

Answer 1

Answer = 5mgh/6

Given h = R/5

Potential Energy at surface of the earth, (PE₁) = -GMm/R²

Potential Energy at height h = R/5 , (PE₂) = -GMm/R + (R/5) = -5GMm/6R

ncrease in Potential energy = PE₂ - PE₁ = -5GMm/6R + GMm/R = GMm/6R

Using g = GM/R² and h = R/5

PE₂ - PE₁ = 5mgh/6

EASY WAY U NEED ?

REFER THE ONE BELOW

Increase in PE = mgR­2 [ 1/R – 1/( R + h)]

Put R = 5h

Incr. in PE = 5mgh/6

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