A body of mass m1 use moving at velocity v. it collides with another stationary body of mass m2. tune get embedded. at the point of collision, the velocity of the system decrease?
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The is a problem with the question.
If the two balls stick together, the collision can not be elastic. In an elastic collision, both the momentum and the translational kinetic energy are conserved. In this situation, some of the kinetic energy must be converted to internal energy, which ultimately becomes randomized and we call it thermal energy. This is an inelastic collision.
Let’s assume that mass m1m1 is moving in the i^i^direction and mass m2m2 is moving in the j^j^direction.
The combined masses after collision will have a momentum of m1vi^+m2vj^m1vi^+m2vj^ or a velocity of m1vm1+m2i^+m2vm1+m2j^m1vm1+m2i^+m2vm1+m2j^
Incidentally the kinetic energies before and after are:
1st massm1v22m1v22
2nd mass m2v22m2v22
combined mass(m12+m22)v22(m1+m2)
If the two balls stick together, the collision can not be elastic. In an elastic collision, both the momentum and the translational kinetic energy are conserved. In this situation, some of the kinetic energy must be converted to internal energy, which ultimately becomes randomized and we call it thermal energy. This is an inelastic collision.
Let’s assume that mass m1m1 is moving in the i^i^direction and mass m2m2 is moving in the j^j^direction.
The combined masses after collision will have a momentum of m1vi^+m2vj^m1vi^+m2vj^ or a velocity of m1vm1+m2i^+m2vm1+m2j^m1vm1+m2i^+m2vm1+m2j^
Incidentally the kinetic energies before and after are:
1st massm1v22m1v22
2nd mass m2v22m2v22
combined mass(m12+m22)v22(m1+m2)
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