A body of mass200g is at rest on smooth surface. A force of 0.2 N acts on it for 5ses. calculate distance travelled by body
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Mass= 200g = 0.2kg
Force = 0.2N
Since, a=F/m=0.2/0.2=1m/s^2
We have,
u=0 , t=5 , a=1 , s=?
s=ut +(1/2)at^2
s= 0 +(1/2)*1*5*5
s= 12.5m
Force = 0.2N
Since, a=F/m=0.2/0.2=1m/s^2
We have,
u=0 , t=5 , a=1 , s=?
s=ut +(1/2)at^2
s= 0 +(1/2)*1*5*5
s= 12.5m
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