Question

A body of mass5 kg moving with velocity of 10 m per second collides head on which a body of mass 2 kg moving with velocity 5 metre per after the impacts , the lighter body has a velocity of 10 metre per second in the original direction . The coefficient of restitution is

Answer 1

Answer:

0.4

Explanation:

By conservation of linear momentum,

$m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}$

Let 5 kg body be body 1 and 2 kg body be body 2,

⇒5X10 + 2X5 = 5X$v_{1}$ + 2X10

⇒$v_{1}$ = 8 m/s

We know that e = $\frac{v_{2}-v_{1}}{u_{1}-u{2}}$

Substituting we get,

e = $\frac{10-8}{10-5}$

⇒e = 0.4