Question

A body of to 10 kg is suspended
Find the values of Fi and F2 Take g = 10 m
​

Answer 1

Answer:

Ref. image I

m=10kg

l=4meter

Ref. image II

In ΔABC,

∠A+∠B+∠C=180

∘

⇒45+90+∠C=180

∘

⇒∠C=45

∘

Ref. image III

System is in equilibrium

⇒∑F

y

=ma

y

=0

⇒T

1

sin45

∘

−mg=0

⇒

2

T

1

=mg⇒T

1

=mg

2

__(I)

∑F

x

=ma

x

=0

⇒F−T

1

cos45

∘

=0

⇒F=

2

T

1

=mg (using eq. (I))

=10×10=100N