Physics, asked by swastika07642, 11 months ago

a body of volume 100 cm cube is immersed completely in water. calculate the up thrust on the body. density of water =10 cube kg/my cube, g=9.8 m/so square ​

Answers

Answered by shabaz1031
36

\red{\boxed{\green{Answer}}}

TO FIND:

The upthrust on the body immersed in water

GIVEN:

Volume of body[V]=100cm³

Body completely immersed

Density of water[D]=10³kg/m

g=9.8 m/s²

Solution;

V=100cm³

=10^-4 m³

upthrust(b)=volume×density×gravity

B=10-⁴×10³×9.8

B=10-¹×9.8

B=0.98N

Thus the upthrust on the body is 0.98N

#AnswerWithQuality

#BAL

Answered by akanksha5826
0

Answer:

volume=100 cm square

Debsity of water = 10cube kg/meter cube

=10power 4 m cube

upthrust(B)=volume*density*gravity

B =10power -4* 10cube*9..8

B= 0.98N

Similar questions