Question

A body of volume 1000cm³ weighs 5kgf in air and it is completely immersed in a liquid of density 1.8g/cm³ find upthrust and weight of body in liquid​

Answer 1

Explanation:

Weight of body in liquid = Actual weight - upthrust

Upthrust exerted =Vρg

Where, V= volume

ρ= density

g=acc. due to gravity

Upthrust=100×10

−9

m

3

×1.8×10

3

kgm

−3

×10

⇒0.18kgf

So, Weight of body in liquid = Actual weight - upthrust

⇒5−0.18=4.82kgf