Question

A body of volume 5 cm^3 and density 7g/cm^3 is immersed in a liquid of density 13 g/cm^3. The apparent weight of the body is ​

Answer 1

Answer:

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Explanation:

Weight of body in liquid = Actual weight - upthrust

Upthrust exerted =Vρg

Where, V= volume

ρ= density

g=acc. due to gravity

Upthrust=100×10

−9

m

3

×1.8×10

3

kgm

−3

×10

⇒0.18kgf

So, Weight of body in liquid = Actual weight - upthrust

⇒5−0.18=4.82kgf

Answer 2

A body of volume 100cm

3

weighs 5kgf in air. It is completely immersed in a liquid of density 1.8×10

3

kgm

−3

. Find the weight of the body in liquid.

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ANSWER

Weight of body in liquid = Actual weight - upthrust

Upthrust exerted =Vρg

Where, V= volume

ρ= density

g=acc. due to gravity

Upthrust=100×10

−9

m

3

×1.8×10

3

kgm

−3

×10

⇒0.18kgf

So, Weight of body in liquid = Actual weight - upthrust

⇒5−0.18=4.82kgf