a body of volume 50 cm3 cube is completely immersed in water find the force of buoyancy on it
Answers
Answered by
33
buoyancy = Vdg. ( d = density , g = gravity)
Fb = 50* 10^-6 * 10^3 * 10.
( d of water = 10^3 , g = 10 )
Fb = 50* 10 ^-2 kg /m ^3
= 0.5 N
Fb = 50* 10^-6 * 10^3 * 10.
( d of water = 10^3 , g = 10 )
Fb = 50* 10 ^-2 kg /m ^3
= 0.5 N
anshika9973:
how can
? .o
brainliest
bcoz i rhink my answer is correct
ya
do you want it in SI unit?
yes
thanks
then in SI unit it will be 49000×10^-5.
i.e 0.49 N
Answered by
35
buoyant force
F=V×d×g
=50×1×980
=49000 dyne,
where v is volume of object immersed or liquid displaced ,d is density of water which is 1g/cc,g is 980cm/s^2.
and since all values are in cgs.therefore the answer is 49000dyne.
F=V×d×g
=50×1×980
=49000 dyne,
where v is volume of object immersed or liquid displaced ,d is density of water which is 1g/cc,g is 980cm/s^2.
and since all values are in cgs.therefore the answer is 49000dyne.
thank
you are welcome.
the answer is then0.49 N in SI unit.
if you find this helpful then you can mark it as brainliest.
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