Question

the speed of the car is reduced from 90 km per hour to 36 km per hour in 5 second what is this what is the distance travelled by the car during this time interval

Answer 1

AHOY !!

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GOOD QUESTION ::-

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Let's start.....

➡Given ,

✔Initial velocity of the car (u) = 90 Km/hr

✔Final velocity of the car = 36 Km/hr

Now convert the velocity in metre per second,

✴u = 90 Km/hr = 90 * 5/18

= 25 m/s

✴v = 36 km/her = 36 * 5/18

= 10 m/s

✴Time taken = 5 sec.

Now , retardation = v - u / t

= 10 - 25 / 5

= -15/5

= -3 m/s ^2

Therefore the distance travelled during this time interval (s) =

s = ut + 1/2 at ^2

s = 25*5 + 1/2 * (-3) * (5)^2

s = 125 + 1/2 * (-3) * 25

s = 125 + (-75)/2

s = 125 - 75/2

s = 175/2

s = 87.5 m

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