A body of weigh 63 N on the surface of earth. What is the gravitational force on it due to earth at a height equal to half the radius of the earth?
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Answered by
1
Answer:
Weight of the body,W=63 N
Acceleration due to gravity at height h from the Earths surface is given by the relation:
g
′
=
(1+
R
e
h
)
2
g
Substituting h=R
e
/2,
g
′
=4g/9
Weight of body of mass m at height h is given as:
W
′
=mg
′
=4/9 mg
=4/9×63=28 N
Answered by
1
as F •{ 1/r^2
R= r+r/2
R^2= 9r^2/4
new f= 4/9×63= 28N
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