Question

a body of weight 64N is pushed with just enough force to start it moving across a horizontal floor and the same force continues to act afterwards if the coefficient of static friction anddynamic friction are 0.6 and 0.4respectively the accerelation of the body will be​

Answer 1

Answer:

Total force: ma=mg(0.6−0.4)

So, acceleration of body is: a=0.2g

Answer 2

Answer:

0.2g

Explanation:

F=ma

f=coefficient of friction * mg

ma=(0.6-0.4)*mg

a =0.2g

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