Question

A body of weight 72 N moves from the surface ofearth at a height half of the radius of earth, thengravitational force exerted on it will be1) 36N2) 32N3)144N4) 50 Nplease help me with this question..​

Answer 1

Explanation:

i.e. we get

gh = 4/9 g

So acceleration due to gravity at a height R/2 above the surface of the earth is 4/9 times to that on the surface of the earth

So weight at that height will be

Wh = m(4/9g) = 4/9 mg

i.e.

Wh = 4/9 W

So weight will be 4/9 times weight at the surface of the earth

We are given weight on the surface of the earth as

W = 63 N, so we have

Wh = 4/9 × 63N = 28 N

So the weight of the body or gravitational force on it due to the earth at a height equal to half the radius of the earth will be 28 N

Answer 2

Answer:

i.e. we get

gh = 4/9 g

So acceleration due to gravity at a height R/2 above the surface of the earth is 4/9 times to that on the surface of the earth

So weight at that height will be

Wh = m(4/9g) = 4/9 mg

i.e.

Wh = 4/9 W

So weight will be 4/9 times weight at the surface of the earth

We are given weight on the surface of the earth as

W = 63 N, so we have

Wh = 4/9 × 63N = 28 N

So the weight of the body or gravitational force on it due to the earth at a height equal to half the radius of the earth will be 28