a body of weight 98N when dipped in water completely displaces 3 litres of water .What will be the weight of body in water and how much buoyant force act on the body in water
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Buoyant Force is a type of force and F=ma.
So,mass of body,
98=m(As acceleration due to gravity is always the same so we don't take it in consideration.)
1)Now,the buoyant force exerted on body by water,
F=ma
F=98 N(We don't take a in consideration.)
2)Weight of body in water(W)=Weight of body in air(we don't take a in consideration so here,mass) - Upthrust or buoyant force.
W=98N - 98N
W=0
Conclusion: The weight of body in water is 0 and the buoyant force exerted on it is 98N.
One more thing,this question is related to physics not maths.
So,mass of body,
98=m(As acceleration due to gravity is always the same so we don't take it in consideration.)
1)Now,the buoyant force exerted on body by water,
F=ma
F=98 N(We don't take a in consideration.)
2)Weight of body in water(W)=Weight of body in air(we don't take a in consideration so here,mass) - Upthrust or buoyant force.
W=98N - 98N
W=0
Conclusion: The weight of body in water is 0 and the buoyant force exerted on it is 98N.
One more thing,this question is related to physics not maths.
Ashwin24:
3 litre of water is not taken in consideration
Yeah
why
Because it has no use.We can calculate the answer even without it.
oh
The thing matter is that the body is completely immersed
I understand
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