Question

a body originally at rest is subject to a acceleration of 4m/s square .find the distance travelled it in (a ) 5seconds (b)in the 5 seconds​

Answer 1

Answer:

தம்ளள்ள

9N9ஹத்Uஇலாஹ்ஹ்

Answer 2

Provided that:

• Initial velocity = 0 mps
• Acceleration = 4 m/s sq.
• Time = 5 seconds

To calculate:

• Distance travelled

Solution:

• Distance travelled = 50 m

Using concept:

• Second equation of motion

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{s \: = ut \: + \dfrac{1}{2} \: at^2}}}}}}$

Where, s denotes displacement or distance or height, u denotes initial velocity, a denotes acceleration and t denotes time taken.

Required solution:

$:\implies \sf s \: = ut \: + \dfrac{1}{2} \: at^2 \\ \\ :\implies \sf s \: = 0(5) + \dfrac{1}{2} \times 4(5)^{2} \\ \\ :\implies \sf s \: = 0 + \dfrac{1}{2} \times 4(25) \\ \\ :\implies \sf s \: = 0 + \dfrac{1}{2} \times 100 \\ \\ :\implies \sf s \: = 0 + 1 \times 50 \\ \\ :\implies \sf s \: = 50 \: m \\ \\ :\implies \sf Distance \: travelled \: = 50 \: m$