Question

A body oscillates with simple harmonic motion according to the equation y(t) = (6.12 m) cos [(8.38 rad/s)t + 1.92 rad]

Answer 1

Answer:

Answer:

(a) 3.267 m

(b) 43.36 m/s

(c) - 229.47 m/s^2

Explanation:

x = 6.12 Cos[8.38t + 1.92]

Compare with the standard equation

x = A Cos (ωt + Ф)

ω = 8.38 rad/s

Ф = 1.92 rad

(A) at t = 1.90 s

x = 6.12 Cos (8.38 x 1.90 + 1.92)

x = 6.12 Cos (17.842)

x = 6.12 (0.5339)

x = 3.267 m

Thus, the displacement at t = 1.9 s is 3.267 m.