Question

a body possesses and initial velocity of 5 metre per second and moves with a uniform acceleration of 2 metre per second calculate the distance would by the body in 4 second​

Answer 1

Equation for distance S travelled by object moving with acceleration a is given by, S = u t + (1/2)a t2 ,

where u is initial velocity and t is time

S = 10×6 + (1/2)×(-2)×6×6 = 60 - 36 = 24 m

Answer 2

Explanation:

Initial Velocity = 5m/s, Acceleration = 2m/s^2 and time = 4 sec

s = ut + 1/2 at^2 (Seconds Equation Of Motion)

s = 5(4) + 1/2 (2) (4)^2

s = 20 + 2/2 × 16

s = 20 + 1 × 16

s = 20 + 16

s = 36 m