Math, asked by magicbeginshere, 8 months ago

Two trains running in opposite directions cross a man standing on the platform in 21 seconds and 11 seconds respectively and they cross each other in 17 seconds. The ratio of their speeds is.

Answers

Answered by siddharthmathavan
0

Answer:

Step-by-step explanation:

It is 3:2

21x +11y = 17x+17y

21x-17x=17y-11y

x/y=4/6 or 6/4

and ration 3:2

Answered by priyagagrai38
2

Answer:

here is your answer..

Step-by-step explanation:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 21x metres,

Length of the second train = 11y metres.

[distance = speed*time]

(21x+11y)/(x+y)=17

=>21x+11y=17x+17y

=>4x=6y

=>x/y=6/4=3/2=3:2

hope it helps you

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