Question

A body projected 30° to the horizontal with velocity 50 m/s find the maximum height :
​

Answer 1

Answer:

Given,

θ=30

0

u=50m/s

g=10m/s

2

Time of flight in projectile motion,

T=

g

2usinθ

T=

10

2×50×sin30

0

T=

g

2×50×0.5

T=5sec

The correct option is B.

hope it will help you please mark me as brainleist