Question

A body projected at an angle 30° has range of 80m . find its maximum height attained . given g=9.8m/s^2​

Answer 1

Answer:

At the top point, horizontal displacement is equal to half the range, vertical displacement is equal to the maximum height of the projectile and time taken is half the time of flight.

Horizontal displacement is:

x=R/2=u²sin(60°)/2x10

=10 root3

Vertical displacement is:

y= 20²sin²(30°)/2×10

=5 m

Time taken is:

t=T/2

= 20 sin(30°)/10

=1s

Average velocity is:

v=s/t

=5 root 13 m/s.

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