Question

A body projected at an angle 30°reaches to a maximum height 15 m. Instead if it is projected vertically upwards with same speed then the maximum height to which it rises is
(a) 7.5 m
(b) 30 m
(c) 20 m
(d) 60 m

Answer 1

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Answer 2

Answer:

Option (d) 60 m

Explanation:

Provided that:

Maximum height (H) = 15 m

Projection angle (θ) = 30°

Suppose the initial velocity = u m/s

In Projectile Motion we Know that;

$h = \frac{ {u}^{2} { \sin }^{2}\theta }{2g} \: ...equation(i)$

So, we may get initial velocity (u) from the equation;

$u \sin\theta = \sqrt{2gh} \\so \: \: u \sin(30\degree) = \sqrt{2 \times 9.8 \times 15} \\ or \: u \: = 34.293 \: m \: .{cm}^{ - 1}$

Now if it is projected vertically upwards with same speed then the maximum height (h');

$h = \frac{ {u}^{2} { \sin }^{2}\theta }{2g} \\ h = \frac{ {(34.293)}^{2} { \sin }^{2}90\degree }{2 \times 9.8} \: m \\ h = 60 \: meter$

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