Question

a body projected vertically up from the top of a tower with 19.6m/s take 5 seconds to reach the ground then height of the Tower is

Answer 1

As given the body is projected upward from tower and finally it comes down on ground
So,displacement of body is equal to height of tower =H
u = 19.6m/s ,g = -10m/s
Here u and g are in opposite direction , so i have taken opposite signs
S=ut+1/2 gt^2
H=19.6×5+1/2 ×-10 ×5×5
H= -27 m
Here '-' indicate that displacement is in downward direction