there are two paths of width 2m each in the middle of a rectangular garden of l3angth 80m and breadth 60m such that one path is parllel to the breadth . find the area of the paths?
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Answered by
14
area of path parallel to length =(2*80)m sq.
=160m sq.
area of path parallel to breadth=(2*60)m sq.
=120m sq.
area of common path = (2*2)m sq.
=4 m sq.
total area of paths = 160m sq +120m sq.-4 m sq.
=280m sq.-4 m sq.
=276m sq.
=160m sq.
area of path parallel to breadth=(2*60)m sq.
=120m sq.
area of common path = (2*2)m sq.
=4 m sq.
total area of paths = 160m sq +120m sq.-4 m sq.
=280m sq.-4 m sq.
=276m sq.
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4
Answer:
Step-by-step explanation:
area of path parallel to length =(2*80)m sq.
=160m sq.
area of path parallel to breadth=(2*60)m sq.
=120m sq.
area of common path = (2*2)m sq.
=4 m sq.
total area of paths = 160m sq +120m sq.-4 m sq.
=280m sq.-4 m sq.
=276m sq.
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