Question

a body projected vertically up reaches a maximum height of 9.8 m. the time of flight is

Answer 1

HEYA!!
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Time of Flight of a Projectile is given by ,

$t = \sqrt{ \frac{2h}{g} } \\ \\ = \sqrt{ \frac{2 \times 9.8}{10} } \\ \\ = \sqrt{ \frac{196}{100} } = \frac{14}{10}$
Hence the Time of Flight is 1.4 Seconds (approx )

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